Post: Officer/Senior Officer

Exam held in: 2017

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Math solution:

1.Two trains of equal length are running on parallel lines in the same direction at 46 kilometre/hour and 36 kilometre/hour. The faster train pass to the slowest train in 36 seconds. The length of each train is-
Solution:
Let ,
The length of each train is x meter
Distance will be x+x = 2x
Relative Speed =46-36
=10 km/hr
=10*(5/18)
= 25/9 m/sec
Distance = Speed*Time
Here,
2x = (25/9) X 36
or,x= 50 (Ans)

2.A man buys tk 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is-
Solution:
Divided on Tk 20
=(9*20)/100
=9/5
Tk 12 income on Tk 100
Tk 9/5 ————=(100/12*9/5)
=15 Tk
Answer:15 Tk
3.By selling an article for TK 100 a man gains tk 15 then his gain percentage is –
Solution:
Here,
Selling Price = tk 100
Gain=Tk 15,
Buying or cost price
=(100-15)=Tk 85,
Therefore Gain % =[(15*100)/85]=17.64%
Answer:17.64%

4.The age of a man is 3 times the sum of the age of his two sons. 5 years hence, his age will be double of the sum of the ages of his sons the father’s present age is-
Solution:
Let ,
The sum of present ages of the two sons be x
Father’s present age = 3x
Here,
(3x + 5) = 2 (x + 10)
Or,3x + 5 = 2x + 20
Or,x = 15.
Father’s present age is
(3*15)=45 years(Answer)

5. If tk 64 amount to 83.20 in 2 years what will tk 86 amount to in 4 years in the same rate percent per annum?
Solution:
Let,
Rate of interest be=r
We know
P=(100*Amount)/(100+r*t)
Or,64=(100*83.20)/(100+2*r)
Or, 6400+128*r=8320
Or,r=15%
Again
P=86 Tk
r=15%
T=4 years
I=(86*15*4/100)
=51.6 Tk
After 4 years amount will be
=(51.6+86)=137.60 Tk
Answer:137.60 Tk

6.A train travels at an average 50 miles per hour for 2.5 hours and then Travels at a speed of 70 miles per hour for 1.5 hours How far did the train travel in the entire 4 hours ?
Solution:
Total distance covers in 4 hrs
=(50*2.5+70*1.5)
=230 miles
Answer:230 miles

8. How many times in a day are the hands of a clock in straight line but opposite in direction?
Solution:
24 hrs in a clock
¤Coincide and Straight line=22
¤Right angle & Acute or obtuse=44

9. The sum of a number and its reciprocal is 1/8 of 34. what is the product of the number and its square root
Solution:
Let
The number be x.
Then,
x + 1/x = 34*1/8
Or,8x^2 – 34x + 8 = 0
Or,4x^2 – 17x + 4 = 0
Or,(4x – 1)(x – 4) = 0
x = 4
Required number
=(4 * √4)
= 4 * 2 = 8.
Answer:8
10. A sum of money invested at compound interest amounts to Tk 4624 in 2 years and to Tk 4913 in 3 years .The sum of money is.
Solution:
Simple interest(3-2)=1 year
=(4913-4624)=289 Tk
SO,
Rate=[(100*289)/(4624*1)]
=25/4 or 6.25%
Let,
Sum of money be=x
Now,
X(1+25/4*100)^2=4624
==================
==================
Or, X=4096 Tk
Answer:4096 Tk

11.If 75% of a number is added to 75. then the result is the number itself .The number is
Solution:
Let,
The number be=x
75% of x + 75 = x
Or, 75/100*x +75=x
Or, 3x/4 + 75=x
==============
==============
Or, x=300
Answer:300
12.A rectangular field be fenced on three sides leaving a side of 20 feet uncovered.if the area of the field is 680 square feet .how many feet of fencing will be required?
Solution:
We know
Length * Breadth = Area

=> 20 * Breadth = 680

=> Breadth = 34 feet

Area to be fenced
= 2B + L
= 2*34 + 20
= 88 feet
Answer:88 feet
13. Two pipes A and B can fill a cistern in 12 minutes and 15 minutes respectively while a third pipe C can empty the full tank in 6 minutes .A and B are kept open for 5 minutes in the beginning and then C is also open. In what time is the cistern emptied –
Solution:
Part filled in 5 min
= 5 * (1/12 + 1/15)
= 5 * 9/60
= 3/4
Part emptied in 1 min when all the pipes are opened
= 1/6 – (1/12 + 1/15)
= 1/60
Now,
1/60 part is emptied in 1min
3/4 part will be emptied in
( 60 * 3/4 )= 45 min
Answer:45 minutes

14.The least number which is a perfect square and is divisible by each of the number is 16,20 and 24 is-
Solution:
LCM of 16,20,24 is =240
Factors of 240 are
=2*2*2*2*3*5
Hence to make 240 a perfect square we need to multiply by 5×3 as they are not in pair.
=240×5×3
=240×5×3
=3600(Answer)

15.Gold is 19 times as heavy as water and copper is 9 times as heavy as water in what ratio should this be mixed to get an alloy r 15 times as heavy as water :
Solution:
Let,
The mass of 1 volume unit of water be 1
Then 1 volume unit of gold has mass 19,
and
1volume unit of copper has mass 9.

Now let g be the volume of gold used, and let c be the volume of copper. The total mass divided by the total volume is the density.

(19g + 9c)/(g + c) = 15

19g + 9c = 15g + 15c

4g = 6c

2g = 3c

g/c = 3/2

The volume ratio is 3:2.

16.The smallest prime number is-
Ans:2

17. X can do a piece of work in 40 days he works at it for 8 days and then Y finished it in 16 days. How long will they take together take to complete the work
Solution:
Work done by X in 8 days
=(1/40*8)
=1/5
Remaining work
=(1-1/5)
=4/5 portion
Now,
4/5 portion work is done by Y in 16
Whole work Y done
=(16*5/4)
=20 days
Both X & Y 1 days work
=(1/40 + 1/20)
=3/40
Hence, X and Y will together complete in=40/3 or 13.33 days
Answer:13.33 days

18. In a 300 m race A beats B by 22.5 metre or 6 seconds. B’s time over the course is
Solution:
B runs 22.5 m in 6 seconds
B runs 300 m in (6×300)/22.5
= 80 seconds
B’s time over the course = 80 seconds
Answer:80 second

19.if the mean of 5 observations X, X + 2 ,X + 4, x + 6 and X + 8 is 11 then the mean of the last 3 observations is-
Solution:
First, you need to solve for x:

(x + x + 2 + x + 4 + x + 6 + x + 8) / 5 = 11

x + x + 2 + x + 4 + x + 6 + x + 8 = 55

5x + 20 = 55

5x = 35

x = 7

Now, substitute for x in each of the last three terms:

x + 4 + x + 6 + x + 8 = (7 + 4) + (7 + 6) + (7 + 8) = (11) + (13) + (15) = 39 / 3 = 13

The mean is 13.

20. A,B,C started business with their investment in the ratio 1 :3 :5 .After 4 month A invested the same amount as before and B as well as C withdrew half of their investment .The ratio of their profit at the end of the year is-
Solution:
Let
Their initial investments be x, 3x and 5x respectively
Then
A:B:C
=(x*4+2x*8):(3x*4+3x/2*8):(5x*4+5x/2*8)
=20x:24x:40x
=5:6:10(Answer)

21. √(√176 + √2401) is equal to-

Ans:15

22.49 pumps can empty a reservoir n 6.5 days, working 8 hours a day . If 196 pumps are used for 5 hours each day ,then the same work will be completed in-
Solution:
Easy solution
(M1*T1)/W1=(M2*T2)/W2
Or,(49*6.5*8)/1=196*5*T2/1
Or, T2=13/5 or 2.6 days
Answer:13/5 days

Pubali Bank Ltd.

Post: Cash Officer (Teller)-2017

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Pubali Bank Written Previous Question Solution

GK Solution:

PUBALI BANK (CASH)-2017

1. What is the position of Bangladesh in ODI Cricket ranking according to ICC?
Ans: 6th
2.What is the name of the diector of the film Muktir Gaan?
Ans: Tareq Masud
3.Which country is known as the sugar bowl of the world?
Ans: Cuba
4.What was the previous name of Comilla?
Ans: Tripura
5. Who is the secretary general of OIC?
Ans: Iyad Bin Amin Madani
6.Madaripur town is located on the river
Ans: Padma
7.In which district is the Payra Sea Port located?
Ans: Patuakhali
8.How many tribes live in the Chittagong Hill Tracts?
Ans: 13
9.The birth place of Professor Armatya Sen was in-
Ans: Manikgonj
10.The first General Election was held in independent Bangladesh on
Ans: 7 march 1973
11.Which one was the first foreign bank of Bangladesh?
Ans: 1st private bank AB bank
1st foreign bank Standard chartered

12.Which country banned smoking first?
Ans: Ireland
13. Who introduced the Bengali calendar?
Ans: Emperor Akbar
14. The oldest tennis tournament in the world is-
Ans: Wimbledon
15. What is the name of the first woman speaker of Jatiya Sangsad of Bangladesh?
Ans: Dr. Shirin Sharmin Chowdhury
16.Which one is the largest Muslim country in the world by population?
Ans: Indonesia
17.Where was the residence of ‘Banganbondhu’ located
Ans: Dhanmondi
18.Awami Muslim League was founded in
Ans: 1949
19. The first European country to recognize Bangladesh?
Ans: East Germany
20.What is the length of Bangbandhu Bridge
Ans:4.8 km
21.Mujibnagar Day observed
Ans:17 April
22.Taj Mahal located
Ans:Agra
23.Taj Mahal Mosque
Answer:Dhaka

Math Solution:

Pubali Bank Teller’17 – Math Solution

26. (8÷88) × 8888088=?
Solution:
8/88×8888088
=8×101001
=808008
27. A and B started a business jointly. A’s investment
was thrice the investment of B and the period of his
investment was two times the period of investment of
B. If B received Tk. 4000 as profit, then their total
profit is:
Solution:
Here, A=3b
Also A’s period two times of B means A=3b×2=6b
So B’s profit= 4000
Therefore A’s profit 6b=4000*6=24000
Total 24000+4000=28000
28. 0.002×0.5=?
Solution: 0.001
29. If x/5=y/8, then (x+5): (y+8) is equal to:
Solution:
Here x/5=y/8 means: x:y = 5:8
So x+5=5+5=10
y+8=8+8=16
Now 10:16=5:8 (ans)
30. Rahim is 40 years old and Karim is 60 years old.
How many years ago was the ratio of their ages 3:5?
Solution:
Let, x years ago
ATQ,
40-x/60-x=3:5 or 3/5
Or, 200-5x = 180x-3x
Or, 2x=20
x=10
31. A man buys an article for 10% less than its value
and sells it for 10% more than its value. His gain or
loss percent is:
Solution:
Let, book value = 100
Buying price at 10% less= 90
Selling price at 10% more= 110
Different = 20
When cost is 90 then profit is 20
When cost is 1 then profit is 20/90
When cost is 100 then profit is (20*100)/90
= 22%+ Ans: More than 20%
32. The difference between the place value and the
face value of 6 in the number 856973 is
Solution:
Face value= 6
Place value=6000
Difference: 6000-6=5994
33. Which one of the following numbers is exactly
divisible by 11?
Solution:
415624 = 4+1+5+6+2+4 = 22
Now 22/11 = 2
34. The mean of 50 observations was 36. It was found
later that and observation 48 was wrongly taken as 23.
The corrected new mean is:
Solution:
Total of 50 observations = 50*36=1800
1800-23=1777
1777+48=1825
Now mean = 1825/50=36.5
35. The simple interest on a certain sum of money at
the rate of 5% p.a for 8 years is Tk. 840. At what rate
of interest the same amount of interest can be
received on the same after 5 years?
Solution:
Interest in per year= 840/8=105
Principle= 105/5*100=2100
Now new interest rate= (840*100)/(2100*5)=8%
36. The sum of three consecutive multiples of 3 is 72.
What is the largest?
Solution:
Here n+n+3+n+6=72
n=21
Largest n+6=27
37. A car moves at the speed of 80 km/hr. what is the
speed of the car in meters per second?
Solution:
80*5/18=22(2/9) m/sec
38. Find the greatest number that will divide 43,91, and
183 so as to leave the same reminder in each case.
Solution:
43/4=10 Reminder 3
91/4=22 Reminder 3
183/4=45 Reminder 3
Ans: 4
39. A shopkeeper purchased 70kg of potatoes for 420
and sold the whole lot at the rate of Tk 6.50 per kg.
What will be his gain percent?
Solution:
Cost price per kg= 420/70= Tk. 6
Prifit= 6.50-6= 0.50
When cost is 6 then profit is 0.50
When cost is 100 then profit is 0.50*100/6
= 8(1/3)%
40. A man has some hens and cows. If the number of
heads be 48 and the number of feet equals 140, then
the number of hens will be:
Solution:
Let, hens number = x
ATQ,
x*2+(48-x)*4=140
2x+192-4x=140
2x=52
x=26
41. A and B can do a piece of work in 5 days; B and C
can do in 7 days; A and C can do it in 4 days. Who
among these will take the least time if put to do it
alone?
Solution:
(A+B)s 1 days work = 1/4
and (A+C)’s 1 day’s work = 1/4
2(A+B+C)s 1 days work = (1/5 + 1/7 + 1/4) = 83/140
(A+B+C)s 1 days work = 83/280
Cs 1 days work = (83/280 – 1/5) = 27/280
As 1 days work = (83/280 – 1/7) = 43/280
Bs 1 days work = (83/280 – 1/4) = 13/280
Thus time taken by A, B, C is 280/43 days, 280/13
days, 280/27 days respectively.
Clearly, the time taken by A is least.
42. 49×49×49×49=7^?
Solution:
7^2×7^2×7^2×7^2
=7^2+2+2+2
=7^8?
Ans: 8
43. After deducting a commission of 5%, a T.V set
costs Tk. 9595. Its market price is:
Solution:
9595*100/95=10100
44. A merchant has 1000kg of sugar, part of which he
sells at 8% profit and the rest at 18% profit. He gains
14% on the whole. The quantity sold at 18% profit is:
Solution:
Let, the quantity sold at 18% profit is = x
ATQ,
.18x + (1000-x).08= 1000*.14
.18x + 80 – .08x = 140
.10x=60
x=600
45. √.0025 * √2.25 * √.0001 = ?
Solution:
.05 * 1.5 * .01
= 0.00075
46. If doubling a number and adding 20 to the result
gives the same answer as multiplying the number by 8
and taking away 4 from the product, the number is
Solution:
Let,
Number=x
According to the question,
2x+20=8x-4
6x=24
X=4
47. 4500 * ? = 3375
Solution:
3375/4500
3/4 (ans)
48. ½ is what percent of 1/3?
Solution:
(1/2)/(1/3)*100
=150%
49. In a dairy farm, 40 cows eat 40 bags of husk in 40
days. In how many days one cow will eat one bag of
husk?
Solution:
40 cows eat 40 bags of husk in 40 days
1 cows eat 40 bags of husk in 40*40 days
1 cows eat 1 bags of husk in 40*40/40 days
Ans: 40
50. Solution: C

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