Uttara Bank Ltd. Written Questions Solution

Uttara Bank Ltd. The written question solution is given below. We publish different educational posts on our website. Exam question solution is one of the most important concerns of our website. Uttara Bank Limited has taken the exam on 02 categorized posts. It’s a lucrative job circular and it’s a great chance to get a job for employment people. This job is perfect for building up a good career. Those, who want to work, should be taken out of this opportunity. Uttara Bank Limited is a renowned private bank in Bangladesh.

 

 

 

 

 

 

 

 

Uttara Bank Ltd. Written Questions Solution:

Bank Name: Uttara Bank PLC

Post: Assistant Officer (Cash)

Written Exam date: 02/02/2018

 

 

Question-01:

Anik visited his cousin Rowhan during the summer vacation. In the mornings, they both would go for swimming. In the evenings, they would play tennis. They would engage in at most one activity per day, i.e. either they went swimming or played tennis each day. There were days when they took rest and stayed home all day long. There were 32 mornings when they did nothing, 18 evenings when they stayed at home, and a total of 28 days when they swam or played tennis. What duration of the summer vacation did Anik stay with Rowhan?
Solution:
Let
The duration of Anik’s vacation be n days.
Given that
On each day, he had engaged in exactly one of swimming and tennis,
Also given that he was free on 32 mornings and
On 18 evenings and on total 28 days he either went for swimming or tennis.
So,
He was busy on (n−32)mornings
And (n−18) evenings
Now we can write,
(n−32)+(n−18)=28
Or, 2n =28+32+18
Or, n=39

So,39 day’s summer vacation did Anik stay with Rowhan
Answer: 39 day’s

 

Question-02:

In a three digit number the number in unit place is 75% of tenth digit number, the tenth digit number is greater than hundred digit by 1 & their sum will be 15, find out the number?

Solution:
Let,
Tenth digit be=y
Unit’s digit= 75% of y=3y/4
Hundred’s digit=y-1
So,
The number be
=100(y-1)+10y+3y/4
=100y-100+10y+3y/4
=(443y-400)/4…………(i)
Now From the Question,
y-1+y=15
or,2y=16
or,y=8
Putting the value of y=8 in equation(i)
(443*8-400)/4
=(3544-400)/4
=(3144/4)
=786
Hence,the required number is 786
Answer:786
Solution-2:
Let,
Unit digit=x
Tenth=y
And,
Hundred=z
So,
Original number=100z+10y+x
From question condition,
x= 75% of y=3/4*y——-(i)
And,
y=z+1———(ii)
Again from question,
y+z=15
Or,2z+1=15
Or,z=7
From equation(ii)
y=8
From (i)
& x=3/4*8=6
So,
Required number=7*100+8*10+6
=786.
Ans:786

See more:
Uttara Bank  PO- Full and Final Questions Solution
Uttara Bank Ltd. Cash Questions Full and Final Solution

 

 

 

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Uttara Bank Ltd. Written Questions Solution:

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