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Janata Bank Executive Officer Written has been taken 5 October 2018. BSCS has taken written exam on 01 categorizes post. It’s a lucrative job and it’s great chance to get job for job seeker. This job is perfect to build up a significant career. Those, who want to work,they should be taken out of this opportunity. BSCS is renowned Government organization in Bangladesh.

Janata Bank Executive Officer Written Question Solution 2018:

Exam Type: Written Exam

Post: Executive Officer (EO)

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Janata Bank Limited (JBL) Exam Question Solution 2019

Exam Date: 5 October 2018

Exam Time: 3.30 PM to 5.30 PM

Exam Taker: Ahsanullah University of Science and Technology (AUST

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Written Math Solution of Exam Taken By AUST

See/download Janata Bank Executive Officer Written Question Solution from below:

Full Question and solution:

1. পদ্মা সেতু বাস্তবায়ন ও বাংলাদেশের আর্থ সামাজিক উন্নয়নে ভুমিকা (৩০)

2. Current Challenges in Banking sector in Bangladesh. Recommendation how to reduce non performing loan (20)

3. Translation B2E (20)

4. Translation E2B (20)

5. You are Planning to set up a food processing factory in Rangamti. Write a letter to a bank manager to finance the factory (20)

6. Passage (20)

7. Math (3 math 25+25+20)=70

Math answer :

A. 100000 TK.

B. 40%

C. 3000 TK.

Full Math Solution:

1. Mr Karim  gave 40% of the money he had ,to his wife . He also gave 20% of the remaining amount to each of his three sons. Half of the amount now left was spent on miscellaneous items and the remaining amount of Tk. 12,000 was deposited in the bank. How much money did Mr. Karim have initially ?

Explanation :

Let the initial amount  with Mr. Karim be Tk. x

Then Money given to wife = Tk. 40100x

= Tk. 2x5    Balance = Tk. (x−2x5) =  Tk. 2x5

Money given to 3 sons =  Tk. [3×(20100×3x5)]

=  Tk. 9x25

Balance = Tk.(3x5−9x25)

= Tk. .6x25

Amount deposited in bank = Tk. (12×6x25)

= Tk. 3x25

3x25 =  12000   ⇔  x=(12000×253)

=  100000

So, Mr Karim initially had Tk. 1,00,000 with him

Short-cut Method :  Let the initial amount  with Mr. Karim be Tk. x

Then ,12[100−(3×20)]

%  of (100 – 40)%  of x

= 12000

⇔ 12×40100×60100×x

= 12000      ⇔325x = 12000  ⇔  x=(12000×253) = 100000

Ans: Tk. 100000

2. A dealer buys dry fruits at the rate of Tk. 100, Tk. 80 and Tk. 60 per kg. He bought them in the ratio Tk. 12 : 15 : 20  by weight. He in total gets 20% profit by selling the first two and at last he finds he has no gain no loss in selling the whole quantity which he had. What was the percentage loss he suffered for the third quantity?

Solution:

Total cost of first two variety = Tk (100×12 + 80×15) = Tk 2400.
Total gain from selling frist two variety = Tk 2400×20% = Tk 480.

So, by selling 20 kg of the third variety of fruit, the dealer suffered a loss of Tk 480.

So, loss per kg of third variety of fruit = Tk. 480 ÷ 20 = Tk 24.

Loss percentage = (24/60 × 100)% = 40%

Answer: 40%

Alternative solution:
Suppose, the dealer suffered a loss of Tk x by selling a kg of the third variety of fruit.

According to the question,
20x = 0.2(100×12 + 80×15)
or, 20x = 480
or, x = 24.

So, the loss percentage = (24×100/60)% = 40%

Shortcut: Solution:

3. In a business A invests 600 more than B. The capital of B remained invested for 7 1/2 months, while the capital of A remained invested for 2 months. If the total profit be Tk. 620 and B gets Tk. 140 less than A gets then what is the amount of A’s Capital?

Solution:

Suppose, the amount of A’s capital is = Tk x
So, the amount of B’s capital is = Tk (x-600)

B’s capital remained invested for 7.5 months.
A’s capital remained invested for (7.5+2) = 9.5 months.
Suppose, total duration of the business is n months.

Suppose,
Out of Tk 620/- profit, B gets = Tk y
So, A gets = Tk (y+140)

So,
y+140+y = 620
or, y = 240

B gets = Tk 240/-
A gets = Tk 240+140 = Tk 380/-

According to the question,
9.5x/n : 7.5(x-600)/n = 380 : 240
19x : 15(x-600) = 19 : 12
15x – 9000 = 12x
3x = 9000
x = 3000

Answer:  3000 TK.

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Janata Bank Executive Officer Written Question Solution 2018:

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